Hey, guys. I know that if I bridge 3 subs(single voice coil 4 ohms), I will get a final load of 1.33 ohms.

My question is - what would be the final load if I bridge 3 subs, but they are single voice coil 3.5 ohms each? And is there a place on-line, where I could use some sort of impedance calculator, so I won't have to bother anyone?

Thanks in advance

1.166 ohms. Parallel connection of multiple subs = sub ohms divided by number of subs = final load.

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I like my gear to be loud and clear.

To late to edit, but I should correct my terminology.

Coil impedance (ohms) divided by number of coils = final load on a parallel connections. Example 2 dual 2 ohm subs wired parallel = .5 ohm load and so on.

A series connection you simply add up the total of the coils to be wired in series.

Example 3 single 4ohm subs wire in series = 12ohms, but not that anybody would do that.

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I like my gear to be loud and clear.

Thank you !!!

If the coils are measuring 3.5 ohms DCR you can consider them to be 4ohm woofers

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SIC Audio